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问题描述：

python随机生成图像旋转任意角度后的图像，需要得到一张图像旋转任意角度之后的结果，随机生成10000张图像，并将输出的图像命名为角度值。

代码实现：

# -*- coding: utf-8 -*-import cv2from math import *import numpy as npimport random# 旋转angle角度，缺失背景白色（255, 255, 255）填充def rotate_bound_white_bg(image, angle):    # grab the dimensions of the image and then determine the    # center    (h, w) = image.shape[:2]    (cX, cY) = (w // 2, h // 2)    # grab the rotation matrix (applying the negative of the    # angle to rotate clockwise), then grab the sine and cosine    # (i.e., the rotation components of the matrix)    # -angle位置参数为角度参数负值表示顺时针旋转; 1.0位置参数scale是调整尺寸比例（图像缩放参数），建议0.75    M = cv2.getRotationMatrix2D((cX, cY), -angle, 1.0)    cos = np.abs(M[0, 0])    sin = np.abs(M[0, 1])    # compute the new bounding dimensions of the image    nW = int((h * sin) + (w * cos))    nH = int((h * cos) + (w * sin))    # adjust the rotation matrix to take into account translation    M[0, 2] += (nW / 2) - cX    M[1, 2] += (nH / 2) - cY    # perform the actual rotation and return the image    # borderValue 缺失背景填充色彩，此处为白色，可自定义    return cv2.warpAffine(image, M, (nW, nH),borderValue=(255,255,255))    # borderValue 缺省，默认是黑色（0, 0 , 0）    # return cv2.warpAffine(image, M, (nW, nH))img = cv2.imread("/Users/Cheney/Downloads/testrotation/1.jpg")l = [random.randint(0, 10000) for a in range(10000)]print(l)for i in l:    imgRotation = rotate_bound_white_bg(img, i)  #  cv2.imshow("img",img)    #cv2.imshow(str(i),imgRotation)    print(i)    cv2.imwrite("/Users/Cheney/Downloads/testrotation/" + str(i) + '.jpg', imgRotation)    #cv2.waitKey(0)